±«Óătv

Elecrochemical cells with only one metal

Two metals are not always required to make a cell. As long as you have one reactive metal to give away electrons and another substance to accept the electrons then you can construct a cell. You also need an ion bridge to allow ions to move between the two solutions.

Some non-metallic substances are found in the Electrochemical series and the same rule applies - the metal, which gives away its electrons, has to be higher in the electrochemical series than the other substance for the cell to produce an electric current. The further apart the metal and the other substance are, the higher the voltage produced by the cell.

Such a cell can be made from nickel dipping into nickel(II) sulfate solution and a carbon rod dipping into a solution of iodine as shown in the diagram below.

Two beakers are connected by an ion bridge. The first beaker holds nickel 2 sulfate solution into which a nickel rod is dipped. The second beaker holds iodine sulfate solution. A carbon rod is dipped into it. The nickel rod is connected to the negative terminal of a voltmeter. The carbon rod is connected to the positive terminal. Electrons are shown flowing from the nickel rod to the carbon rod, giving a reading of 0.8 volts on the voltmeter.
Figure caption,
Electrochemical cell with nickel in nickel sulfate and carbon in iodine solution

In this reaction the nickel atoms give away electrons and change into nickel(II) ions:

\(Ni(s) \to Ni_{}^{2 + }(aq) + 2e_{}^ - \)

The iodine molecules accept these electrons and change into iodide ions.

\(I_2^{}(aq) + 2e_{}^ - \to 2I_{}^ - (aq)\)

The overall equation for the reaction is:

\(Ni(s) + I_2^{}(aq) \to NiI_2^{}(aq)\)

Related links