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Moles and masses - Higher

There is a relationship between a (Ar) or (Mr), and the of one of a substance:

Some examples are given in the table below.

SubstanceFormulaAr or MrMass of 1 mol (g)
CalciumCa40.140.1
OxygenO22 × 16.0 = 32.032.0
Calcium carbonateCaCO340.1 + 12.0 + (3 × 16.0) = 100.1100.1
SubstanceCalcium
FormulaCa
Ar or Mr40.1
Mass of 1 mol (g)40.1
SubstanceOxygen
FormulaO2
Ar or Mr2 × 16.0 = 32.0
Mass of 1 mol (g)32.0
SubstanceCalcium carbonate
FormulaCaCO3
Ar or Mr40.1 + 12.0 + (3 × 16.0) = 100.1
Mass of 1 mol (g)100.1

This relationship is useful because it makes it possible to work out the mass of reactants needed to make a particular mass of product. It is also possible to work out which reactant will be used up.

Calculating number of moles

The number of moles of a given mass substance is calculated using:

Use Ar instead of Mr for metals or separate .

Question

Calculate the number of moles of carbon atoms in 6.0 g of carbon. (Relative atomic mass: C = 12.0)

Calculating masses

To calculate the mass if given the number of moles and the relative formula mass, the equation must be rearranged to make mass the subject.

One way to remember this is ‘mass equals mister mole’.

Question

Calculate the mass of 0.25 mol of carbon dioxide molecules. (Relative formula mass: CO2 = 44.0)

Example

Question

Calculate the mass of 0.125 moles of iron. (Relative atomic mass: Fe = 55.8)